如何修改动态消息?
我是这么用的:
wx.cloud.callFunction({
name: 'CreateActivity'
}).then(succ => {
console.log('CreateActivity', succ);
let activityId = succ.result;
Global.UNG.Temp.ActivityId = activityId;
wx.updateShareMenu({
withShareTicket: true,
isUpdatableMessage: true,
// isPrivateMessage: true,
activityId: activityId, // 活动 ID
templateInfo: {
parameterList: [{
name: 'member_count',
value: '1'
}, {
name: 'room_limit',
value: '2'
}]
}
});
WeAppService.shareAppMessage({
title: '{}想和你进行决斗 (比赛:{})'.format(nickname, r),
imageUrl: 'wx-res/share_225_180.png',
query: `stageId=${stageId}&roomKey=${roomKey}&gameuidv2=${gameuidv2}&nn=${nickname}&lv=${lv}&avatar=${avatar}&avatarUrl=${avatarUrl}`,
});
});
我遇到的问题是动态消息没法修改
不知道哪里错了,返回ok:
// 云函数入口函数
exports.main = async (event, context) => {
return new Promise((resolve, reject) => {
let { userInfo, activityId } = event
cloud.openapi.updatableMessage.setUpdatableMsg({
activityId: activityId,
targetState: 1,
templateInfo: {
parameterList: [{
name: 'member_count',
value: '2'
}, {
name: 'room_limit',
value: '2'
}]
}
}).then(_ => {
resolve(_);
}).catch(err => {
reject(err);
});
});
}
1 回复
找到答案了:
如果需要targetState:1 (已完成)状态。那么parameterList里面需要参数path和version_type。(昨天没看清文档)
但我还是不太清楚微信设计这两个参数必填有何用意?
cloud.openapi.updatableMessage.setUpdatableMsg({
activityId: activityId,
targetState: 1,
templateInfo: {
parameterList: [{
name: 'path',
value: 'closed=1'
}, {
name: 'version_type',
value: 'develop'
}]
}
}).then(_ => {
resolve(_);
}).catch(err => {
reject(err);
});