如何在A页面调用wx.scanCode拿到参数发起异步请求后直接跳转至B页面而不返回A再跳转至B？
发布于 6 年前 作者 xiulan44 5049 次浏览 来自 问答

API：scanCode

基础库：2.4.4

微信版本号：7.0.4

问题：在A页面呼起扫一扫，在扫一扫的成功回调里发起异步请求，请求的成功回调里navigateTo B页面。总是在调起扫一扫后重回A页面而后才跳转B页面，如何直接跳至B页面？

代码：

jumpPay: function(e) {
        wx.scanCode({
            success(res) {
                let str = res.result
                let q={}
                str.replace(/([^?&=]+)=([^&]+)/g,(_,k,v)=>q[k]=v);
                // q;
                // str = str.match(/qrcode=(\S*)/)[1];
                console.log('扫一扫获得的res',q)
                if(q.qrcode){
                    const getScanQuery = {qr_code:q.qrcode}
                    PayStore.getQueryScanInfo(getScanQuery).then(function(res) { // 发起异步请求
                        if(0==res.data.retcode){
                            let query = {...res.data,...getScanQuery}
                            query = JSON.stringify(query)
                            wx.navigateTo({
                                url: '/pages/pay/payInput?query='+query
                            });
                        }else{
                            console.log('接口回参错误')
                        }
                    }).catch( (error) => {
                        console.log(error)
                    })
                    
                }else{
                   console.log('未获取到qrcode')
                }
            },
            fail(){
                console.log('扫一扫调用失败')
            }
        })
     
    },
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