部分测试号运行时代码无法运行,一个号可以正常显示,一个号就无法正常使用setdata
发布于 7 年前 作者 jingzhong 6654 次浏览 来自 官方Issues

部分代码,加载时使用了异步等待,断点测试发现是这个返回查询函数中无法运行if,其他测试号就可以正常运行,主账号开始可以用,点了清除缓存后也无法运行了,有些测试号就可以运行

queryplayer() {

return new Promise((resolve, reject) => {

var _this=this

const db = wx.cloud.database()

// 查询当前用户所有的 counters

db.collection(‘room’).where({

room_number: this.data.room_number,

room_password: this.data.room_password

}).get({

success: res => {

console.log(’ 返回数据queryplayer’, res)

// this.setData({

// queryback: res.data[0],

// avatarUrl: res.data[0].playercard,

// select_card: res.data[0].select_card

// })

var queryback = res.data[0]

var avatarUrl = res.data[0].playercard

var select_card = res.data[0].select_card

var index_check_seat = wx.getStorageSync(‘index_check_seat’)

if (index_check_seat > avatarUrl.length){

var index_check_seat=0

}

if (index_check_seat < avatarUrl.length) {

var check_card = avatarUrl[index_check_seat][0].check_card

var seatup_state = avatarUrl[index_check_seat][0].peopleseat

if (seatup_state) {

_this.setData({

game_start: avatarUrl[index_check_seat][0].start,

jn: avatarUrl[index_check_seat][0].jn,

gamelist: queryback.gamelist,

qbtqr: avatarUrl[index_check_seat][0].qbtqr

})

}

_this.setData({

check_card: check_card,

nextseat_number: index_check_seat,

})

}

_this.setData({

queryback: queryback,

avatarUrl: avatarUrl,

select_card:select_card,

select_rule: queryback.select_rule,

select_card_source: queryback.select_card_source,

dayopen_steta: avatarUrl[index_check_seat][0].dayopen_steta,

music_index: queryback.music_index,

})

for (let i = 0; i < queryback.select_card_source.length; i++) {

if (queryback.select_card_source[i].name == ‘丘比特’) {

this.setData({

qbt_qlqr_show: true

})

break

}

}

console.log(’ 返回数据this.data.queryback ', this.data.queryback)

resolve(“ok”)

},

fail: err => {

wx.showToast({

icon: ‘none’,

title: ‘网络错误’

})

console.error(’[数据库] [查询记录] 失败:’, err)

}

})

})

},

2 回复

未复现问题,麻烦更新工具版本再重试

解决了,把setdata分开写两次就好了,可能是数据大的原因吧,当检测到未运行时,在调用这个函数,就可以了

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