程序的意思就是调用wx.request返回结果拼接个字符串然后再用wx.request发出去，用了函数内变量temp, 全局变量app.data.globaldata都试过，怎么都不能把第一次返回结果给到第二次发送的输入变量中。谁能告诉我怎样搞，搞的我对小程序都没信心了。

// pages/ssq/ssq.js

const app = getApp();

Page({

/**

  * 页面的初始数据

  */

data: {

newnumber1: ‘0’,

newnumber2: ‘0’,

newnumber3: ‘0’,

newnumber4: ‘0’,

newnumber5: ‘0’,

newnumber6: ‘0’,

newnumber7: ‘0’,

gb: app.globaldata

},

/**

  * 生命周期函数–监听页面加载

  */

onLoad: function (options) {

var that = this

var oldnumbers = “01,04,09,21,31,33,05,0,0,0,0,0,0”

var old1 = “01,04,09,21,31,33,05,”

var temp = ‘’

wx.showLoading({

title: ‘上传中’,

})

GetGetUserData(oldnumbers).then(GetGetUserData(old1 + temp +",00,00,00,00,00"))  //temp试过，app.data.globaldata都试过了，都不行。

wx.hideLoading()

//获取用户信息

function GetGetUserData (ssqdata) {

var that1 = that;

return new Promise(function (resolve, reject) {

wx.request({

url: ‘https://xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx’,

method: ‘POST’,

data: {

lastnumbers: ssqdata

},

header: {

‘content-type’: ‘application/json’ // 默认值

},

success: function (res) {

console.log(res.data)

that.setData({ gb: res.data })

temp = res.data

resolve();

}

})

})

}

}

})