信道服务出现错误
发布于 6 年前 作者 leiwei 12008 次浏览 来自 问答

打开信道出现如下错误。

{"code":0,"data":{"invalidTunnelIds":[]},"message":"OK"}

java.lang.Exception: 信道服务器响应格式错误，无法解析 JSON 字符串

at com.qcloud.weapp.tunnel.TunnelAPI.request(TunnelAPI.java:112)

at com.qcloud.weapp.tunnel.TunnelAPI.emitPacket(TunnelAPI.java:72)

at com.qcloud.weapp.tunnel.TunnelAPI.emitMessage(TunnelAPI.java:54)

at com.qcloud.weapp.tunnel.TunnelAPI.emitMessage(TunnelAPI.java:43)

at com.qcloud.weapp.tunnel.TunnelRoom.broadcast(TunnelRoom.java:72)

at com.qcloud.ChatTunnelHandler.broadcast(ChatTunnelHandler.java:138)

at com.qcloud.ChatTunnelHandler.onTunnelMessage(ChatTunnelHandler.java:93)

at com.qcloud.weapp.tunnel.TunnelService.handlePost(TunnelService.java:212)

at com.qcloud.weapp.tunnel.TunnelService.handle(TunnelService.java:78)

实现代码：

[@RequestMapping](/user/RequestMapping)
    public void service(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        System.err.println(WxAuthenticationUtils.getWxid(request));
        // 创建信道服务处理信道相关请求
        TunnelService tunnelService = new TunnelService(request, response);
        try {
            // 配置是可选的，配置 CheckLogin 为 true 的话，会在隧道建立之前获取用户信息，以便业务将隧道和用户关联起来
            TunnelHandleOptions options = new TunnelHandleOptions();
            options.setCheckLogin(true);
            // 需要实现信道处理器，ChatTunnelHandler 是一个实现的范例
            tunnelService.handle(new ChatTunnelHandler(), options);
        } catch (ConfigurationException e) {
            e.printStackTrace();
        }
    }
回到顶部